Submission

Score: 100

User: Bestzu

Problemset: อะนาแกรม 2

Language: cpp

Time: 0.002 second

Submitted On: 2025-10-14 09:33:28

#include<bits/stdc++.h>
#define endl '\n'
using namespace std;

int main() {
    ios::sync_with_stdio(false); cin.tie(nullptr);

    string s1, s2; cin >> s1 >> s2;
    int freq1[8] = {0};
    int freq2[8] = {0};
    for(char c : s1) {
    	freq1[c - 'A']++;
	}
	for(char c : s2) {
		freq2[c - 'A']++;
	}
	for(int e : freq1) {
		cout << e << " ";
	}
	cout << endl;
	for(int e : freq2) {
		cout << e << " ";
	}
	cout << endl;
	int diff = 0;
	for(int i = 0; i < 8; i++) {
		cout << abs(freq1[i] - freq2[i]) << " ";
		diff += abs(freq1[i] - freq2[i]);
	}
	cout << endl;
	if(diff <= 3) cout << "anagram";
	else cout << "no";
    return 0;
}