Submission

Score: 100

User: sulinx

Problemset: อะนาแกรม 2

Language: cpp

Time: 0.003 second

Submitted On: 2025-11-10 22:10:28

#include <bits/stdc++.h>
using namespace std;

int main(){
    int count1[8] = {0};
    int count2[8] = {0};
    int sum = 0;

    string str;
    cin >> str;
    for(int i = 0;i<str.length();i++){
        count1[str[i]-65]++;
    }

    cin >> str;
    for(int i = 0;i<str.length();i++){
        count2[str[i]-65]++;
    }

    for(int i = 0;i<8;i++){
        cout << count1[i] << " ";
    }cout << '\n';

    for(int i = 0;i<8;i++){
        cout << count2[i] << " ";
    }cout << '\n';

    for(int i = 0;i<8;i++){
        count1[i] = abs(count1[i] - count2[i]);
        cout << count1[i] << " ";
        sum+=count1[i];
    }cout << '\n';

    if(sum>3){
        cout << "no";
    }else{
        cout << "anagram";
    }
}