Submission

Status:

(PPPPPPPPPP)(PPPPP)(PPPPP)(PPPPPPPPPP)

Subtask/Task Score:

{20/20}{30/30}{30/30}{20/20}

Score: 100

User: C12

Problemset: กองไฟ

Language: cpp

Time: 0.004 second

Submitted On: 2026-03-09 23:10:01

#include <bits/stdc++.h>

using namespace std;

const int mod = 1e9+7;

long dp[51][51][51][3][3] = {0};

int main(){
    ios::sync_with_stdio(0);
    cin.tie(0);

    int n,a,b,c;

    cin >> n >> a >> b >> c;


    dp[0][0][1][2][2] = 1;
    dp[0][1][0][1][1] = 1;
    dp[1][0][0][0][0] = 1;

    for(int i = 0;i <= a;i++){
        for(int j = 0;j <= b;j++){
            for(int k = 0;k <= c;k++){
                for(int f = 0;f < 3;f++){
                    if(i > 0){
                        dp[i][j][k][0][f] += (dp[i-1][j][k][1][f] + dp[i-1][j][k][2][f]) % mod;
                    }
                    if(j > 0){
                        dp[i][j][k][1][f] += (dp[i][j-1][k][0][f] +  dp[i][j-1][k][2][f]) % mod;
                    }
                    if(k > 0){
                        dp[i][j][k][2][f] += (dp[i][j][k-1][0][f] + dp[i][j][k-1][1][f]) % mod;
                    }
                }
            }
        }
    }

    long out = 
        (dp[a][b][c][0][1] + dp[a][b][c][0][2]) +
        (dp[a][b][c][1][0] + dp[a][b][c][1][2]) +
        (dp[a][b][c][2][0] + dp[a][b][c][2][1]);

    out %= mod;
    
    cout << out;

    return 0;
}

/*

7 16
This is an example of text justification.

6 16
What must be acknowledgement shall be

*/