Submission

Score: 100

User: bossc

Problemset: อะนาแกรม 2

Language: cpp

Time: 0.002 second

Submitted On: 2026-05-10 14:25:13

#include <iostream>
#include <string>
#include <cmath> // Included to use abs()

using namespace std;

int main() {
    string d1, d2;
    int ctr = 0;
    
    // Read the two strings
    cin >> d1 >> d2;
    
    // Arrays to store counts for A-H
    int arr1[8] = {0}, arr2[8] = {0};
    
    // Count characters for the first string
    for (char i : d1) {
        arr1[i - 'A']++; // Using 'A' is functionally identical to 65 but easier to read
    }
    
    // Count characters for the second string
    for (char i : d2) {
        arr2[i - 'A']++;
    }
    
    // Print the counts for the first string
    for (int i = 0; i < 8; i++) {
        cout << arr1[i] << " ";
    }
    cout << endl;
    
    // Print the counts for the second string
    for (int i = 0; i < 8; i++) {
        cout << arr2[i] << " ";
    }
    cout << endl;
    
    // Calculate, print, and sum the absolute differences
    for (int i = 0; i < 8; i++) {
        int diff = abs(arr1[i] - arr2[i]);
        cout << diff << " ";
        ctr += diff; // Add the actual difference, not just 1
    }
    cout << endl;
    
    // Check if the total difference is 3 or less
    if (ctr <= 3) {
        cout << "anagram\n";
    } else {
        cout << "no\n";
    }
    
    return 0;
}