Submission

Score: 60

User: The3e

Problemset: อะนาแกรม 2

Language: cpp

Time: 0.004 second

Submitted On: 2026-09-25 19:34:17

#include <iostream>
#include <string>
using namespace std;

int main() 
{
    string s1, s2;
    int a[8] = {0};
    int b[8] = {0};
    int sum;
    
    cin >> s1;
    cin >> s2;
    
    for(int i = 0; i < s1.length(); i++) {
        a[s1[i] - 'A']++;
    }
    for(int i = 0; i < s2.length(); i++) {
        b[s2[i] - 'A']++;
    }
    
    for (int i = 0; i < 8; i++) {
        cout << a[i] << " ";
    }
    cout << endl;
    for (int i = 0; i < 8; i++) {
        cout << b[i] << " ";
    }
    cout << endl;
    
    for (int i = 0; i < 8; i++) {
        int c = a[i] - b[i];
        
        if(c < 0) {
            c = -c;
        }
        cout << c << " ";
        
        sum = sum + c;
    }
    cout << endl;
    
    if (sum >= 3) {
        cout << "no";
    }
    else {
        cout << "anagram";
    }
    
    return 0;
}