Submission

Score: 90

User: karnsinee

Problemset: อะนาแกรม 2

Language: cpp

Time: 0.003 second

Submitted On: 2025-09-24 20:58:17

#include<bits/stdc++.h>
using namespace std;
int main (){
	string a,b;
	int n,m,count1[10]={0},count2[10]={0},c[8]={0},sum;
	cin>>a>>b;
	n=a.size();
	m=b.size();
	for(int i=0;i<n;i++){
		count1[a[i]-'A']++;
	}
	for(int i=0;i<m;i++){
		count2[b[i]-'A']++;
	}
	for(int i=0;i<=7;i++){
		cout<<count1[i]<<" ";
	}
	cout<<"\n";
	for(int i=0;i<=7;i++){
		cout<<count2[i]<<" ";
	}
	for(int i=0;i<=7;i++){
		if(count1[i]!=count2[i]){
			c[i]++;
			sum++;
		}
	}
	cout<<"\n";
	for(int i=0;i<=7;i++){
		cout<<c[i]<<" ";
	}
	cout<<"\n";
	if(sum>3){
		cout<<"no";
	}
	else{
		cout<<"anagram";
	}

}