Submission

Score: 100

User: navysrimuang

Problemset: ตรวจบัตรเครดิต

Language: cpp

Time: 0.002 second

Submitted On: 2025-09-26 22:59:10

#include<bits/stdc++.h>
#define endl '\n'
using namespace std;

int main(){

  string s;
  cin >> s;
  int key = s[15] - '0';
  int sum = 0;
  for(int i = 0;i<15;i++){
    //take sum of normies
    if(i%2 != 0){
      sum += s[i] - '0';
    }else{
      int tmp = s[i] - '0';
      tmp*=2;
      string stmp = to_string(tmp);
      for(int j = 0;j<stmp.length();j++){
        sum += stmp[j] - '0';
      }
    }
    //if its every odd *2 and take sum
  }
  int ans = (10 - (sum%10))%10;
  if(ans == key){
    cout << "yes" << endl;
  }else{
    cout << "no" << endl;
  }
  return 0;
}