Submission

Score: 100

User: letdown

Problemset: อะนาแกรม 2

Language: cpp

Time: 0.002 second

Submitted On: 2025-10-09 09:13:50

#include <iostream>

using namespace std;
int freq1['H'-'A'+1];
int freq2['H'-'A'+1];
int main() {
    string s1, s2;
    cin >> s1 >> s2;
    int d = 0;
    for (auto c : s1) freq1[c-'A']++;
    for (auto i : freq1) cout << i << " ";
    cout << endl;
    for (auto c : s2) freq2[c-'A']++;
    for (auto i : freq2) cout << i << " ";
    cout << endl;

    for (int i = 0; i < 'H'-'A'+1; i++) {
        int t = abs(freq1[i] - freq2[i]);
        d += t;
        cout << t << " ";
    }
    cout << endl;
    if (d <= 3) cout << "anagram";
    else cout << "no";
}